h^2-22h-7=0

Solution for h^2-22h-7=0 equation:

h^2-22h-7=0

a = 1; b = -22; c = -7;
Δ = b2-4ac
Δ = -222-4·1·(-7)
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-16\sqrt{2}}{2*1}=\frac{22-16\sqrt{2}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+16\sqrt{2}}{2*1}=\frac{22+16\sqrt{2}}{2}
$